What is the relative humidity if a sample of air holds 0.01 kg of moisture at 21°C when the maximum it can hold is 0.015 kg?

Prepare for the 5th Class Power Engineering Exam with comprehensive flashcards and multiple-choice questions. Each question includes hints and explanations. Get exam-ready!

Relative humidity is a measure that expresses the current amount of moisture in the air compared to the maximum amount it can hold at a given temperature, and it is usually expressed as a percentage. To calculate relative humidity, you can use the formula:

[

\text{Relative Humidity} = \left( \frac{\text{actual moisture content}}{\text{maximum moisture capacity}} \right) \times 100%

]

In this scenario, the actual moisture content is 0.01 kg and the maximum moisture capacity at 21°C is 0.015 kg. By substituting these values into the formula:

[

\text{Relative Humidity} = \left( \frac{0.01 , \text{kg}}{0.015 , \text{kg}} \right) \times 100%

]

First, you divide 0.01 by 0.015, which gives you approximately 0.6667. When you multiply this by 100%, you get:

[

0.6667 \times 100% \approx 66.7%

]

Therefore, the relative humidity of the air sample is accurately assessed as 66.7%.

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