If the refrigerant is R-12 and the evaporator operates at -15°C (5°F) with a specific volume of 0.09102 m³/kg, what is the mass of refrigerant per minute for a volume compressed of 45.24 m³/h?

To determine the mass of refrigerant flowing per minute, we can use the relationship between specific volume, volume flow rate, and mass flow rate. The mass flow rate is calculated using the formula:

[

\text{Mass Flow Rate} = \frac{\text{Volume Flow Rate}}{\text{Specific Volume}}

]

In this case, the volume flow rate is 45.24 m³/h. First, we need to convert this flow rate from cubic meters per hour to cubic meters per minute. Since there are 60 minutes in an hour:

[

\text{Volume Flow Rate} = \frac{45.24 \text{ m}^3/\text{h}}{60} = 0.754 \text{ m}^3/\text{min}

]

Next, we apply the specific volume provided in the problem, which is 0.09102 m³/kg. We can now use the mass flow rate formula:

[

\text{Mass Flow Rate} = \frac{0.754 \text{ m}^3/\text{min}}{0.09102 \text{ m}^3/\text{kg}} \approx 8.28 \text{