How much heat is required to melt 1 tonne (1000 kg) of ice at 0°C in 24 hours?

To determine how much heat is required to melt 1 tonne (1000 kg) of ice at 0°C in 24 hours, one needs to consider the latent heat of fusion for ice. The latent heat of fusion is the amount of heat necessary to convert ice into water at the same temperature, which is approximately 334 kJ/kg.

For 1 tonne (1000 kg) of ice, the calculation for the heat required to melt it would be as follows:

Heat required = mass × latent heat of fusion

Heat required = 1000 kg × 334 kJ/kg = 334,000 kJ or 334 MJ.

However, in the context of refrigeration and cooling systems, we can express this in terms of tonnes of refrigeration. One tonne of refrigeration corresponds to the amount of heat absorbed to melt 1 tonne of ice in 24 hours, which is equivalent to the daily heat requirement for this process.

Thus, the choice indicating "1 tonne of refrigeration" effectively describes the method of a cooling system facilitating the melting of ice over a specified period, linking the thermodynamic principles to a practical cooling capacity. It encapsulates the necessary heat transfer while emphasizing the practical application of refrigeration technology.

Therefore, in this